Page 22 - Math Grade 11 (Advance)

PROEUS DARA

I:Slg an+ -a = I +4a" (1 +4a ) = 4(a a ) (1)
1 11 11 1 11 11 _ 1
11 1
d5t~H'iltlbn=a + 1 -a" tSldl(1) bRQIS bn=4b"_ ~bbn =4
II 1
StlriSJ n ~
IJ

.. .. 0
!Uri (b") ctldrn!Dtl!Uri (a ) ffl'!:H'i513S mmg n?::2 tRQIS
IJ IJ 11 u n
1 1
n-1 n 11
_ ~ k _ l 1 z n- 1 _ I x ( 4 - I) _ 4 - 1 '1
an - a1 + ""-' 4 - + 4 + 4 + ... + 4 - 4 1 - -3-
k = 1
.. " .. "" 4"- 1
tlutsg ri9 n &S !Uri (a") R an = - - '1
u IJ IJ 3
1
.J79 C»C» 0 C»
Uf.!Jf1113 tRtL'i5~rid~tu (r 11 ) ~tH1jdr:litln an+ 1 -r,
1
~ 1 1 1 4 ( 1)
i:R<1J rn = - i:RQIS a 11 + 1 + = 1 + 4a, + = 4a" + = 4 · a 11 +
3 3 3 3 3
1
1
""
mtl VII+ 1 = all+ I + 3 t'Ul tu vll = all + 3 ( 1) '1
"" n-I
tRQIS vn+ I = 4VIl t'Ul tu VII = 4 . VI
4
l
""
' 0
tRHluRrulSl VI ffl139Sln9Stl (!) R VI = ai + 3 = 3
0
11 1
&RQIS Vn = 4 - · ~ = ~ · 4" tRHllJRMSl a ffl139SlRflStl (1)
11
&Rffli:l r = a· n + p (<X, Ptda) ctl~ri
11
1
tRQIS hl~iil~ ft:J r:t5Hlu2j

11
an+I = l+4a <=><X·(n+l)+~= 1+4·(<X·n+~) Y. 3·<X·n+3·~-<X+l =0
3·<X=0 .. 1
t'Ul tu <X = 0 ' p = - - '1
{ 3·~-a+l=O 3

t'Ul~&sg rl1 =- ~ ~msg~fj (rll) t'Uli&l~rid~ru '1
1 1

17