Page 26 - Math Grade 11 (Advance)
P. 26

PROEUS DARA













           0     I  0
          rnun ~Hu      ~f) (a 11 )  Firul~&i::JlliJ  al  =  1  ,  az  =  13  ,  an+2  = an+1+6a 11
                   u
                         I
                         0   I   Ql   \;)   Ql
          (n  =I,  2 ... )  '1  nrulfl~9 n  i:Sf151  '1
                                       1
                      0   I   QJ   ':)   Ql
                     nrulfl~9 n  I:Sf1ri  (a  )
                                         11
                                    1
               all+2  =  all+l + 6an ~ a,+2 -an+l- 6a,  =  0
                  C»   0   •   •   2                    C»
                t'U13f11HtHflbli  .  x  -x-6 =  0   tS"Hytutu13f11~  X=  3  u_  x  = -2  £R(f18

                 a,+z+2an+l ~ 3(an+I +2a")      (i)
               {                                (ii)
                                     1
                 all+  2 - 3a +  1  - -2(a +  - 3a 11 )
                         11        11
               (i)   an+z+2an+l  = 3(all+ 1 +2a,J

                mtl  b  "  = all+ l   +2  an   tSlot'd- (b)  r:hMflmo.fhnunrl:jru'i:flsorum'"~m13tt'dsb  3
                                                                             U  u
                                              n
                                                                                    ....
                                         4  61
                61
                                       o
                                                    ll
                                         1           1
            Ql   C»   c:::il                         c::.             1
          I:Ulli5~9 1  R  bl  = az+2a1  = 13 +2X l = 15  2t\  b = 15 · (3)"-
                                                          11
                                         ll  1
                i:Rti12  an+ +2a = 15·(3)       (1)
                          1
                               11
                                          Il-l
                i:Rti18  all+  1 - 3a"  = 10 · (-2)   (2)  '1

                m13  o)  stJ  (2)  tRms

                     an+ I  +2a = 15  · (3)"-l   (I)
                             11
                   {
                    an+ l- 3an  = 10. (-2)"  l   (2)




                        n-1         n-1           11
               an=  3x3     -  2 x(-2)   = 3"+(-2)
                                                       11
                ~msg ~9 n  t2~fl (an)  ~all= 3"+(-2)
                                I
                         QJ       0   I      0   I  0
                        f151  (a  )   nrulntf:!lli598ln9Sti  a = 0  ,  a 2  = 3  ,  alz+2  = 4an+ I- 3an
                              11                       1
                         1
                          0   1   .Q1   ':;l   .Ql
          (n =  l'  2,  ... )  '1  nruln~9 n  t2 f151  (all)  '1
                                         I
                                                                                          21
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