Page 19 - Math Grade 11 (Advance)
P. 19

PROEUS DARA






                en=  16+6(n-l) = 16+6n-6 = 6n+ lO

                                             n-!         n-!
                thmg  122:2  tl:lQIS  bn  = b +  ~ ck  = 14+ ~ (6k+ 10)
                                          1
                                             k =I        k  =I
                                   n-!
                           =  14+6 ..L,k+l0(12-l) =  14+6·;zn(n-1)+10(12-1) =  3n  2 +7n+4
                                                          1
                                   ""'
                                  k =I
                 0
                mmg  12  =    tl:lQIS  b =  4 + 7 + 3  =  14  Clfi  '1
                                      1
                                              n-l        n-l
                                                               2
                                           1
                ~tmg  n<::2   tl:lQlS  an=a +~bk=4+~(3k +7k+4)
                                              k = l      k =  l
                                             n-!     n-!
                                                 2
                                                k
                                                        k
                                      =  4 + 3 ~  + 7 ~ + 4(n- 1)
                                             k = l   k =I
                                              1                   1
                                      = 4 + 3 ·  12(12- 1 )(2n- 1) + 7 ·  (12- 1 )n + 4n- 4
                                              6                   2
                                   1             2                       2        3    2
                                 =  (12-1)(7n+2n  -n)+412  =  (n-1)(3n+n  )+4n = n  +2n  +n
                                   2
                                3    2
                           an= n  + 212  + n  '1
                                     0   "o   C»
                2.  l:lrt.fiSltHlitH1  n  nl::l'i.HltSMfi  (an)
                             u      u   u   d
                                             1
                   mtl  sn  thtHli'iJntsfiJn  (an)  ~
                                       1


                         n       n
                                          2
                   sn  = ~ak = ~(k +2k +k)
                                     3
                        k=l     k=l




                        1  2     2    1                1
                      =  :q:n  (l+n)  +2· n(n+1)(2n+1)+ n(n+l)
                                      6                2
                        1               2
                      =  n(n + 1 )(3n + 3n  + 4 + 8n + 6)
                        12
                        1           2
                      =  n(n + 1)(3n  + lln + 10)
                        12







                       0    •   t:::l1   '1:)   C»
                       firt.fln~&l  n  tS~n  1,  2,  5,  12,  27,  58,  121, ...  '1
                                      1
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