Page 141 - Math Grade 12 (Advance)
P. 141

PROEUS DARA

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                   aaa  ,  3aa  ,  a3a  ,  aa3  ,  33a  ,  3a3  ,  a33  ,  333  '1  L::lutsg  X  ffititi5Rnl:13
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                                                          5  5  5    125
                   P(X = 0)  =  P(aaa)  =  P(a) X P(a) X P(a)  = 6 X 6 X 6 =
                                                                     216
                                                          1  5  5)    75
                   P(X= 1)  =  P(3aa)+P(a3a)+P(aa3)  = 3  6x6x6  =   216
                                                         (
                                                          1 1 5)
                                                         (            15
                   P(X = 2)  = P(33a) + P(3a3) + P(a33)  = 3  6 X 6 X 6  =
                                                                     216
                                                 2 6
                   P(X = 3)  = P(333)  = ~X~ X~ =  ~
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                   u                       u

                                 X            0          1         2         3

                                              125       75        15         1
                              P(X = x)
                                             216       216        216       216




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                                                            X       1     2    3     4    5
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                                                        P(X = x)   0.1   0.3   c    0.2   0.1



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                   R.  &;&13             2.  P(2s;x ::;4)             ~.  P(X < 3)  '1
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