Page 140 - Math Grade 12 (Advance)

PROEUS DARA

1.2. ufn.nwtunurmu
II
CJ <' ...
1.}5QltHfjruQlSf!1rulSlQb~Vl'ifiHl..fl~iHru HltHt5HhlHh P(X = 0) = 0.25
u 1
P(X = 1) = 0.5 sb P(X = 2) = 0.25 ~n:JH15~ : Po = 0.25 ' Pr = 0.5 Sb Pz = 0.25 '1

X 0 I 2

P(X = x) 0.25 0.5 0.25

ou u ~ ~
mnbtSH'UliGl mnb'iHrt.nbmnn~Ql'i.HS~HGHtH:jSJ X '1
u

Nwusw : 1UQlli P(X = x) tfj rumtitvlabnt'i§S'tHiF)tSHtG~trH:iSt X
L,; (3- 6\1 u t.!
u
t'UlimtH'rt.nbfcrnlJOlU '1
u

t[tl ti5 X, y, r,... '1

0 eJ eJ P(X = x)
utrt.nb &UnlJOlUHIGUnLnnrutttl ruLmu :
u
d5 x r:llHto~ccr~sJ tfjrurunnt~

0.5 - - - - - - - -
P(X = x ) = p 1 , P(X = x ) = p 2 ,
2
1
0.25
P(X = x ) = p 3 , .•. , P(X = x") = p" t Sl g Lf=1U X; Qb
3
1
0 0
rutflhlruTin &f!1QlS p +p +p + ... +p = 1 ~ X
1
2
3
11
0 2
LP(X =X;) = 1 l{tttlru~ Lp; = 1 '1
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