Page 13 - Math Grade 11 (Advance)
P. 13

PROEUS DARA




                          15
                      n.  2: (4k + 3)
                         k =I

                          20
                      ~.  2: (k+3)k
                         k =I

                          15           15     15       15    15
                      n.  2: ( 4k + 3)  =  2: 4k + 2: 3  =  4 2: k + 2: 3
                         k=l          k=l    k=l      k=l   k=l






                          20           20           20       20
                                                        2
                                           2
                      ~.  2(k+3)k =  2(k +3k)  =  ~k +3~k
                         k=l          k=l          k=l      k=l





                                  = J0  X  7 X  41  + 3 X  21  X  10  =  2870 + 630  = 3500
                                     20
                         f:HU1Sl  n.  ~(3k+l)
                                    k =  1






                                     14
                                 ?1.  ~ (4k-3)
                                    k=4
                                      n
                                 li5.  ~(3+k)  2

                                     k=l
                                     30
                                 i:l.  ~ k(k+ 1)
                                    k =I













          8
   8   9   10   11   12   13   14   15   16   17   18