Page 12 - Math Grade 11 (Advance)
P. 12

PROEUS DARA








                     n
                 n.  ~ = nc
                       c
                    k =I
                     n             n      n                  n            n      n
                 ~.  ~ (ak + bk)  = 2: ak + 2: bk        '1.15.  2: (ak- bk)  = 2: ak- 2: bk
                    k=l           k=l    k=l                k=!          k=l    k=l
                     n              n       n        n
                 b.  ,L (ak + bk) =  2: a~+ 2 2: akbk + 2: b~
                               2
                    k=l           k=l      k=l      k=l






                     n
                 n.  2: c  = c + c + c + ... + c  = nc
                    k =I

                     n                                                         n
                 2.  ,L cak  =  ca + ca 2  + ca + ... +can  =  c(a + a + a + ... +an)  =  c 2: ak
                                                        1
                               1
                                        3
                                                            2
                                                                3
                    k =  1                                                    k =I
                     n
                 ~.  2(ak+bk) = (a 1 +b )+(a 2 +b )+ ... +(an+bn)
                                       1
                                                2
                    k = 1
                                                                      n      n
                              = (a 1  + a 2  + ... +an)+ (b 1  + b 2  + ... + bn)  = 2: ak + 2: bk
                                                                    k =I   k =I
                     n
                '1.15.  2(ak-bk) = (a -b )+(a -b )+(a -b )+ ... +(an-bn)
                                                      3
                                                          3
                                                2
                                       1
                                    1
                                             2
                    k= 1





                     n             n                   n       n         n
                 b.  2 (ak + bk) = 2: (a~+ 2akbk + b~) = 2: a~+ 2: 2akbk + 2  b~
                              2
                   k=l            k=l                 k=l    k=I       k=I






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