Page 41 - Math Grade 12 (Advance)

PROEUS DARA

t1'1ft91 : d5 C(x) mtlunrh~runrutu;-uqhmHHli~tu1f1~= x 'LI=1]h ts-u

C(x) = C~x) dlLfl1l'h~runru'!3wJ1:3qhmHHli~tu1f1~: 1 t1J1]h") '1

-1 I 0 eJ cJ ';I r:J C!p 1 0
c (x) dlLtnncrrun ru1:3wJ'!3 m~'!3t1:1 ru'i:flsnt~[Yttn rushLtnncrrun ru'ewJ'e
mrurunnm~ru~n'i:3tRS'!3rutlnm '1
n "' IJ

mumiit: 'iQ1Riirun rutumnb'!3ti5ti5Q1ulH5W'in'!3tii Sd ru~ tu'i:m: t'ithtnW'etlJ§'i
u t_; 1"' u n L.:. 1 .n t_;t_; u tJ
1 I
ffl'!3H~f:1'!3S C(x) = 0.125i+20x+ 1000 ~~dlmstDru ~t:iru x dl'l51'i:fln.JHt51f1~=

dru~ms'i

n. Rrt.nSl C(lOO) , C(120) sb C(l50) '1

0 t f! I 0
2. nrul~H~t1'!32Ltnncrrun ru'ewJ'e '1
R. tirulSlLtnRiirunru1:3wJ'!3'i5t~'!3filn.Jrun X= 100 ' X= 120 sb X= 150 '1
tuiim :
N

n. 1=1rulSl C(lOO) , C(120) Sb C(150)
2
tf:1'i:fl2 ccx>=O.l25x +20x+woo mscuru
2
tf:1Q1S C(100) = 0.125x 100 +20x 100+ 1000 = 4250 mscuru
2
C(120) = 0.125x 120 +20x 120+ 1000 = 5200 mscuru
2
C(l50) = 0.125x 150 +20x 150+ 1000 = 6812.5 mscuru '1
c< • 0
2. H~f:1'!32LQlncrrunru'!3wJ'!3
2
tf:1'i:flS C(x)=0.125x +20x+1000 mscuru
1000
tf:1Ql2 C(x) = 0.125x + 20 + m s 'U ru 'i
X
• 0 "'
?1. Lmncr run ru'!3wJ'!3'!5&~'!3
1000
tti'i:fl2 C(x) = 0.125x+20+ mscuru
X
t1:1ms c'cx) = o.t25- woo m 2 'U ru

1000
c'< IOO) = o.I25- 2 = o.o25 m 8 'U ru
100
1000
c'(l20) = 0.125- 2 = 0.055 m8curu
120

1000
c'(I50) = 0.125- 2 = 0.08 m8tDru 'i
150
36 .