Page 72 - Math Grade 11 (Advance)
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PROEUS DARA


                 t?!Ql£  0 <X s  ~  ,  0 <  sinx s  ~  Ln~Stl  2bt < x s ~ + 2krc
                                               u











                                        2              2
                      t?i'i:fl£  2cos2x + sin xcosx + sinxcos x > 2(sinx + cosx)
                            2
                 2(cos\- sin x) + sinxcosx(sinx + cosx)- 2(sinx + cosx) > 0

                 ( cosx + sinx)[2( cosx- sinx) + sinxcosx- 2] > 0
                 ffitl  f(x)  = ( COSX + Sinx )[2( COSX- sinx) + SiUXCOSX- 2]

                ttnru  f(x) thH£?JY2f[:jru'i:fl£2ti  2n:  t2lgt?JUlut'dnn'ltu-Hm~nbmsu (O,  2n:)  '1
                               1            I,J                ;j'       01   ....
                                                                         1
                 t?!Ql£  f(x)  =  0  ,  cosx + sinx  = 0  ( 1)  ~ 2( cosx- sinx) + sinxcosx- 2 = 0   (2)

                 ( 1 )  :  tanx  =  -1  ,   (  x =  3n:   , x =  7n:)   '1
                                                4
                                       4
                 (2)  mb  t  = cosx-sinx  =  J2cos(x+~)  t[:jru  -J2srsJ2



                          2                  .         1-i
                         t  =  I- 2sinxcosx  ,  smxcosx = -  -
                                                        2
                                        2
                                    1 - t           2
                 (2)  ffiutuHtu~ 2t+---2 =  o  ~  -4t+3  =  o
                                                   t
                                      2



                                                                                      3n:
                 t= I  ,J2,cos(x+~) = l  ,  cos(x+~) = f =cos~ '1  t?!Ql£  x  = 0   '   X - -





                                   3n:         3n:              7n:
                     X    0                                               2n:
                                    4                            4
                                          +                               +
                   f(x)





                 7n:
                 4  + 2b < x < 2n: + 2b  ( k E 'Z)  '1



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